Hello Aspirants,
Welcome to Online Quants Test in AffairsCloud.com. We are starting IBPS PO Prelim 2016 Course and we are creating sample questions in Quants section, type of which will be asked in IBPS PO 2016 !!!
 Click Here to View Stratus: IBPS PO 2016 Course
 IBPS PO Prelim 2016: Reasoning Test
 IBPS PO Prelim 2016: Quant Test
 IBPS PO Prelim 2016: English Test
Help: Share Our IBPS PO 2016 Course page to your Friends & FB Groups
_____________________________________________________________________
Quizsummary
0 of 10 questions completed
Questions:
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
Information
All the Best
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading...
You must sign in or sign up to start the quiz.
You have to finish following quiz, to start this quiz:
Results
0 of 10 questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 points, (0)
Categories
 Quantitative Aptitude 0%
 1
 2
 3
 4
 5
 6
 7
 8
 9
 10
 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude6, 2, 10, 1, 28, 12, ?
Correct
Explanation:
2^2, +2^3, 3^2, +3^3, 4^2,Incorrect
Explanation:
2^2, +2^3, 3^2, +3^3, 4^2, 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude8832, 544, 64, 14, 6, ?
Correct
Explanation:
8832/16 – 16/2 = 544
544/8 – 8/2 = 64
64/4 – 4/2 = 14
14/2 – 2/2 = 6
6/1 – 1/2Incorrect
Explanation:
8832/16 – 16/2 = 544
544/8 – 8/2 = 64
64/4 – 4/2 = 14
14/2 – 2/2 = 6
6/1 – 1/2 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude2, 4, 7, 35, 42, ?
Correct
Explanation:
Prime numbers
*2, +3, *5, +7, *11Incorrect
Explanation:
Prime numbers
*2, +3, *5, +7, *11 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative Aptitude7, 16, 34, 61, 97, ?
Correct
Explanation:
7 + 9*1, 16 + 9*2, 34 + 9*3, 61 + 9*4, ..Incorrect
Explanation:
7 + 9*1, 16 + 9*2, 34 + 9*3, 61 + 9*4, .. 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative Aptitude8, 2, 2, 4.5, 18, ?
Correct
Explanation:
*0.5^2, *1^2, *1.5^2, *2^2, *2.5^2,Incorrect
Explanation:
*0.5^2, *1^2, *1.5^2, *2^2, *2.5^2, 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeFind the total surface area of a right circular cylinder whose volume is 4928 cubic cm and surface area is 704 square cm.
Correct
Explanation:
ᴨ r^2 h = 4928, 2ᴨrh = 704
Divide both equations, r = 14
TSA of cylinder = surface area + 2ᴨ r^2 = 704 + 2ᴨ(14^2)Incorrect
Explanation:
ᴨ r^2 h = 4928, 2ᴨrh = 704
Divide both equations, r = 14
TSA of cylinder = surface area + 2ᴨ r^2 = 704 + 2ᴨ(14^2) 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeA can do thrice as much work as B can complete in a day. C can complete half as much work as A and B do together can complete in a day. If C alone can complete a work in 33 days, then in how many days A alone would complete the work?
Correct
Explanation:
A does half as much work as B does in a day. So if A does work in 3x days, then B in x days.
So A+B completes 1/x + 1/3x = 4/3x work in a day, or completes a work in 3x/4 days.
Now C does half as much work as A and B do together in a day. So if A+B in 3x/4 days, then C in 2 * 3x/4 = 3x/2 days
So 3x/2 = 33, solve, x = 22 days, so A in 3*22 daysIncorrect
Explanation:
A does half as much work as B does in a day. So if A does work in 3x days, then B in x days.
So A+B completes 1/x + 1/3x = 4/3x work in a day, or completes a work in 3x/4 days.
Now C does half as much work as A and B do together in a day. So if A+B in 3x/4 days, then C in 2 * 3x/4 = 3x/2 days
So 3x/2 = 33, solve, x = 22 days, so A in 3*22 days 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA box contains 2 blue, 3 green and 5 red balls. If three balls are drawn at random, what is the probability that exactly 2 balls are same in color?
Correct
Explanation:
Total balls = 10
Case1: 2 blue, 1 green or red
So prob. = ^{2}C_{2}×^{8}C_{1/10C}_{3} = 1/15
Case2: 2 green, 1 blue or red
So prob. = ^{3}C_{2}×^{7}C_{1/10C}_{3} = 21/120
Case3: 2 red, 1 green or blue
So prob. = ^{5}C_{2}×^{5}C_{1/10C}_{3} = 5/12
Add all casesIncorrect
Explanation:
Total balls = 10
Case1: 2 blue, 1 green or red
So prob. = ^{2}C_{2}×^{8}C_{1/10C}_{3} = 1/15
Case2: 2 green, 1 blue or red
So prob. = ^{3}C_{2}×^{7}C_{1/10C}_{3} = 21/120
Case3: 2 red, 1 green or blue
So prob. = ^{5}C_{2}×^{5}C_{1/10C}_{3} = 5/12
Add all cases 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeTwo alloys contain copper and zinc in the ratio of 2 : 3 and 3 : 5 respectively. 25 kg of first alloy, 40 kg of second alloy and some quantity of pure copper are melted together. If in final alloy the ratio of copper and zinc is 11 : 8, find the amount of pure zinc that is melted.
Correct
Explanation:
In 1st alloy copper = (2/5)*25 = 10kg and zinc = 2510 = 15
in 2nd alloy copper = (3/8)*40 = 15kg and zinc = 4015 = 25
So, (10+15+x)/(15+25) = 11/8
Solve for x, x = 30Incorrect
Explanation:
In 1st alloy copper = (2/5)*25 = 10kg and zinc = 2510 = 15
in 2nd alloy copper = (3/8)*40 = 15kg and zinc = 4015 = 25
So, (10+15+x)/(15+25) = 11/8
Solve for x, x = 30 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe ratio of the ages of A and B is 8 : 11. C’s present age is 3 less than B’s age plus half of A’s age. If the ratio of C’s present age and B’s age 3 years hence is 7 : 6, find the total of the ages of all of three.
Correct
Explanation:
A/B = 8/11
8x and 11x
So C’s present age = (11x + 8x/2) – 3 = 15x – 3
So (15x3)/(11x+3) = 7/6
Solve, x = 3
So total = 8x+11x+15x3 = 34x – 3Incorrect
Explanation:
A/B = 8/11
8x and 11x
So C’s present age = (11x + 8x/2) – 3 = 15x – 3
So (15x3)/(11x+3) = 7/6
Solve, x = 3
So total = 8x+11x+15x3 = 34x – 3
_____________________________________________________________________
 Note: We are providing unique questions for you to practice well, have a try !!
 Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
 Share your Marks in Comment Sections